Factor.
3x^2 + 5x + 2 = 0
expand (3x+2)(x+1) and see what you get.
sorry...
I still don't get it
Have you not studied and learned this?
To factor the quadratic equation 3x^2 + 5x + 2 = 0, we need to find two binomials that, when multiplied, give us the original equation.
First, we look at the coefficient of x^2, which is 3. We then need to find two numbers that multiply to give us 3 multiplied by the constant term (2), which gives us 6, and add up to the coefficient of x (5).
Let's try different combinations:
1 * 6 = 6
2 * 3 = 6
Considering the second combination, if we take 2 and 3 and set up the factors, we have:
(2x + 1)(3x + 2) = 0
Expanding this equation, we get:
(2x)(3x) + (2x)(2) + (1)(3x) + (1)(2) = 0
6x^2 + 4x + 3x + 2 = 0
Combining like terms, we have:
6x^2 + 7x + 2 = 0
As you can see, this is not the original equation. Therefore, the correct factorization of 3x^2 + 5x + 2 = 0 is (3x + 1)(x + 2) = 0.