posted by Anonymous .
The experiment requires 1 mg per ml of iron. what masss of iron (III) nitrate hexahydrate (Fe(NO3) - 6H2O) would you need to dissolve in 1 litre to achieve this value?
I would start by figuring the decimal percentage of Fe in that compound.
Then, to get 1mg fe,you need masscompound*percentage of the compound, or the masscompound to get 1mg is 1mg/percentagecomposition
Then,you need 1000 times that much to make a liter.
so i would find the percent of iron in the compound, and then find the total mass of the compound and multiply it by the percent of iron that i found?