Physics

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In a game of basketball, a forward makes a bounce pass to the center. The ball is thrown with an initial speed of 3.9 m/s at an angle of 25 degrees above the horizontal. It is released 0.75 m above the floor.
What horizontal distance does the ball cover before bouncing?

  • Physics -

    Break up the initial velocity in to horizontal and vertical components.

    vertical
    Vi=3.9sin25
    hf=ho+vi*t-4.9t^2
    0=.75+3.9sin25*t-4.9t^2 solve for time in air, t.
    Then
    Horizontal
    distance=3.9cos25*t

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