1.Write an equation for the line that is parallel to x = -35 and passes through the point (7, 12).

2.Write an equation for a horizontal line that passes through the point (5, -2).

To find the equation for a line that is parallel to a given line and passes through a given point, we can use the slope-intercept form of a linear equation, which is in the form y = mx + b.

1. For the line parallel to x = -35, notice that the equation x = -35 is a vertical line with an undefined slope. Since a line parallel to a vertical line must also be vertical, its equation will also be x = a constant value.

Therefore, a line parallel to x = -35 will have an equation of x = some constant value. Since it passes through the point (7, 12), the equation of the line will be x = 7.

2. For a horizontal line passing through the point (5, -2), we know that a horizontal line has a slope of 0. This means that the equation will be in the form y = b, where b is the y-coordinate of the given point.

Using the point (5, -2), we can substitute the values into the equation y = b:
-2 = b

Therefore, the equation of the horizontal line passing through the point (5, -2) is y = -2.