if you have 66.6g NH3 how many grams of F2 are required for a complete reaction?
PLEASE SHOW ALL WORK AND/OR STEPS!!!!
sar i am in 6th cant help you
To find out how many grams of F2 are required for a complete reaction with 66.6g NH3, we need to use the balanced equation:
NH3 + F2 → NF3 + H2
The molar mass of NH3 is 17.03g/mol, and the molar mass of F2 is 38.00g/mol.
Step 1: Calculate the number of moles of NH3 using its molar mass.
Number of moles = mass / molar mass
Number of moles of NH3 = 66.6g / 17.03g/mol ≈ 3.906 mol
Step 2: Determine the stoichiometry of the balanced equation. The balanced equation tells us that the ratio of NH3 to F2 is 1:1. This means that for every 1 mole of NH3, we need 1 mole of F2.
Step 3: Calculate the number of moles of F2 required.
Number of moles of F2 = Number of moles of NH3 ≈ 3.906 mol
Step 4: Convert moles of F2 to grams using its molar mass.
Mass = number of moles × molar mass
Mass of F2 = 3.906 mol × 38.00g/mol ≈ 148.428g
Therefore, approximately 148.428 grams of F2 are required for a complete reaction with 66.6 grams of NH3.
To determine the number of grams of F2 required for a complete reaction with 66.6g of NH3, we need to use the balanced chemical equation for the reaction between NH3 (ammonia) and F2 (fluorine gas).
The balanced chemical equation is:
NH3 + F2 -> NF3 + HF
From the equation, we can see that the moles of NH3 and F2 have a 1:1 ratio. Therefore, we need to convert the mass of NH3 to moles and then convert the moles of NH3 to moles of F2 using the stoichiometry of the reaction. Finally, we convert the moles of F2 into grams.
Step 1: Calculate the moles of NH3:
Molar mass of NH3 (ammonia) = 14.01 + 3(1.01) = 17.03 g/mol
Moles of NH3 = mass / molar mass = 66.6 g / 17.03 g/mol = 3.9065 mol
Step 2: Use the stoichiometry of the reaction to find the moles of F2:
According to the balanced equation, the ratio of NH3 to F2 is 1:1.
Therefore, moles of F2 = moles of NH3 = 3.9065 mol
Step 3: Convert moles of F2 into grams:
Molar mass of F2 (fluorine gas) = 2(19.00) = 38.00 g/mol
Mass of F2 = moles of F2 x molar mass = 3.9065 mol x 38.00 g/mol = 148.267 g
Therefore, for a complete reaction, you would need 148.267 grams of F2.