when 25.0 of lithium iodide completely dissolves in water how much heat is evolved
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Well, well, well, looks like we've got some chemistry conundrum here, don't we? Now, I don't want to trigger any explosive reactions, but let me lighten things up with a joke before we continue: Why did the scarecrow win an award? Because he was outstanding in his field! Now onto your question!
When lithium iodide dissolves in water, an exothermic reaction occurs, meaning it releases heat. The exact amount of heat evolved will require some calculations involving the enthalpy of dissolution and other factors, but I don't want to bore you with all those numbers. Instead, let's say that it would be enough heat to warm the heart of a snowman. So, keep your water and lithium iodide away from any frozen friends because things could get heated up in no time!
The amount of heat evolved when a certain quantity of lithium iodide (LiI) completely dissolves in water can be calculated using the equation:
q = m * ΔH
where:
q is the heat evolved,
m is the mass of the substance (in this case, lithium iodide), and
ΔH is the enthalpy change of the dissolution process.
To determine the heat evolved, we need to have the enthalpy change value (ΔH) for the dissolution process of lithium iodide. Unfortunately, that information is not provided in the question.
The enthalpy change for a chemical reaction or process is typically measured experimentally and reported in units of either J/mol or kJ/mol. Without knowing the specific enthalpy change value for lithium iodide dissolving in water, it is not possible to calculate the exact amount of heat evolved.
If you have access to the enthalpy change value for the dissolution of lithium iodide in water, please provide it, and I can help you calculate the heat evolved.
To calculate the amount of heat evolved when a given mass of lithium iodide dissolves in water, you need to know the enthalpy change of the dissolution process, also known as the heat of solution.
The heat of solution for lithium iodide can be found in a reference source such as a chemistry handbook or online database. Let's assume it is -60.0 kJ/mol.
To determine the heat evolved when 25.0 g of lithium iodide dissolves, you'll need to follow these steps:
1. Convert the mass of lithium iodide (in grams) to moles. To do this, use the molar mass of lithium iodide, which is 133.85 g/mol. You can calculate the number of moles using the formula: moles = mass (g) / molar mass (g/mol).
moles = 25.0 g / 133.85 g/mol
moles ≈ 0.187 mol
2. Multiply the number of moles by the heat of solution to find the amount of heat evolved. Use the equation: heat evolved (kJ) = moles × heat of solution (kJ/mol).
heat evolved = 0.187 mol × -60.0 kJ/mol
heat evolved ≈ -11.22 kJ
The negative sign indicates that the process is exothermic, meaning heat is released. Therefore, approximately 11.22 kJ of heat is evolved when 25.0 g of lithium iodide completely dissolves in water.