College Algebra
posted by Ashley .
Translate the problem into a pair of linear equations in two variables. Solve the equations using either elimination or substitution. State your answer for both variables.
The perimeter of a rectangle is 72m. If the width were doubled and the length were increasd by 9m, then the perimeter would be 114m. What are the dimentions?

College Algebra 
bobpursley
2L+2W=72
2(2W) + 2(L+9)=114
check that. 
College Algebra 
Ashley
Does this mean that the dimentions are 72 and 114 or do you take it father to find what w & l are which I think might be w=12 and l=24. does that sound right?

College Algebra 
bobpursley
Of course you have to find width w, and length L.
I would go back and check W=12, L=24 in the original equations. If they check, you are home bound.
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