Post a New Question

Physics

posted by .

On the lower left corner of a square is a fixed charge qLL = 1.5x10^-9 C and on the loser right corner is a fixed charge qLR = 4.0x10^-9 C. The square has a side length L = 0.25 meters.

a) Find the electric potential energy of a third charge q = -6x10^-9 C placed at the upper left corner of this square.

b) Find the potential energy of this same third charge q placed at the upper right corner of the square.

  • Physics -

    Easy. Potential is a scalar, so add the voltage from each of the other charges.

    Upper left Potential

    V=kqLL/sidelength + kQLR/diagonal length

    Then the electric potentialenergy of the third charge is

    V*q

    Do the same technique for the last charge, add the voltage potential from the three charges, then for elec potential energy, that sum times qur.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question