MATH
posted by BRENDON .
24 1c coins are set out in a row on a table. Then
every 2nd coin is replaced by a 2c coin
every 3rd coin is replaced by a 5c coin
every 4th coin is replaced by a 10c coin
every 5th coin is replaced by a 20c coin
every 6th coin is replaced by a 50c coin
every 7th coin is replaced by a $1 coin
After all the exchanges have been carried out, what is the total amount left on the table?
Please help, the answer suppose to be $6.30 but I got $7.04?
Thank you

In the end, you have the following values:
coin value
7 $1
14 $1
21 $1
6 .50
12 .50
18 .50
24 .50
5 .20
10 .20
15 .20
20 .20
4 .1
8 .1
16 .1
2 .05
22 .05
the remaining all are .01
I count 16 above out of 24 coins, or .01*8
check my thinking. 
you are wrong it is 6.30 that's what i got

Hi Mariela, could you please tell me how you got $6.30. Explanation above still added over $6.30, I'm confused.
Thanks