Physics
posted by Alan Thomas .
A person standing at the edge of a seaside cliff kicks a stone over the edge with a speed of vi = 23 m/s. The cliff is h = 54 m above the water's surface. How long does it take for the stone to fall to the water?
With what speed does it strike the water?

If the initial velocity is horizontal, it has not influence on the time of fall.
Time of fall is determined by the height, and by gravity.
h=1/2 g t^2
solve for t, time. 
Thank you.

How would I calculate the speed?

the vertical speed is
vf= g *time
the horizontal speed is the kicking speed.
Vftotal=sqrt (Vh^2+ Vvf^2)
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