# Trigonometry

posted by .

How do you factor and simplify,
1-sin^3x

and
sec^4x-2sec^2xtan^2x+tan^4x

• Trigonometry -

the first is the difference of two cubes:

(1-a^3)=(1-a)(1+a+a^2)
from...
a3 – b3 = (a – b)(a2 + ab + b2)

the second is very similar to

(a^2-2ab+b^2).....

• Trigonometry -

I'm not positive, but the answer to 1-sin^3 would be (1-sinx)(1+sinx+sin^2x)

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