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intergrate(e^5x)/((e^10x)+4)dx

  • Math -

    Let e^5x = u
    Then
    5 e^5x dx = du
    The integral becomes
    INT (1/5)u/[u^2 +4] du
    Now let v = u^2 + 4
    dv = 2u du
    The integral becomes
    (1/10) INT (1/v)dv
    = (1/10)ln v = (1/10) ln(u^2 + 4)
    = (1/10)ln(e^10x + 4)

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