posted by tim .
At what projection angle will the range of a projectile equal to 6 times its maximum height?
I know its easy but ive been absent and missed class!
max height occurs when Vv=0
solve for t.
then put it in
solve for max height
Then, multiply it by six, and set it equal to VcosTheta*2*time (twice the time to the max height).
Prepare yourself for messy algebra.