Algebra 1
posted by bubba .
A cheetah is 300 feet from its prey. It starts to sprint toward its prey at 90 feet per second. At the same time, the prey starts to sprint at 70 feet per second. When will the cheetah catch its prey?

Xp = 300 + 70 t (Prey location)
Xc = 90 t (Cheetah location)
t is in seonds and the X's are in feet.
The prey will be caught when Xp = Xc
300 + 70 t = 90 t
20 t = 300
Solve for t