# MATH/ALGEBRA PLEASE

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I am having a real issue with this one problem
the problem is : y=1/3x-3
I am supposed to graph the problem and then find the y intercept.

First I substituted x with 12.
Y=1/3(12)-3
s divided by 12 is 4, now I subtract 3from 4 and get 1
therefore, my first set reads(12,1)
I do the same operations for the second set, but this time I use 15, now I have my second set ( 15,2)

So mu ordered pairs are (12,1) and ( 15,2)

My y intercept is (0,-3)

Did I do this right or is my answers wrong?

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