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physics

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A 4.0 kg particle is moving along the x axis to the left with a velocity of v= -12.0 m/s. Suddenly, between times t =0 and t = 4.0 x a net force = 3t^2 – 12t is applied to the particle, where F is in N and t is in s. Calculate the velocity of the particle at t=4.0 s. Can I just substitute 4 in this formula 3t^2 - 12t to solve

  • physics -

    you have to calculate acceleration.

    a= force/mass= (3t^2-12t)/4
    v(4)=-12+a*t
    now put t=4 into the equation

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