posted by Claire .
e) Adjust the amplitude control of the function generator until the signal has a 6V peak-to-peak swing. The resultant form will have the following mathematical equation:
v = Vm sin2(pi)ft = 3sing2(pi)500t
f) The sinusoidal signal 3sin2(pi)500t has an effective value determined by:
Veff = 0.707(3V) = 2.121V
Connect the DMM directly across the function generator in the ac rms mode and adjust the oscilloscope output until Veff = 2.121V. Then connect the output of the function generator directly to the scope and note the total peak-to-peak. Is the waveform the same as that obtained in part (e)? Explain.
Can someone pls tell me whether they should be the same or dfferent? Thanks!
They should be the same, if the input impedance of the Oscilloscope and DMM are very high.