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Write the slope intercept form of an equation for the line that passes through (5,3) and is parallel to x+3y=6 . Please help me solve!!!!!!!!!!

  • Math -

    put the given equation into slope intercept form.

    y=-1/3 x +6
    so the slope is -1/3

    Now, your new line will be of the form

    y=mx+b. To be parallel, it must have a slope of -1/3.
    y=-1/3 x + b
    Now put the point on the line (5,3), and solve for b, and you have it, both m, and b.

  • Math -

    How would you solve for b?

  • Math -

    put y=3, x=5 into
    y=-1/3 x+ b
    solve for b.

  • Math -

    ok thank you!! I got y=1/3x+4/5

  • Math -

    well that is not right at all.

    y=-1/3 x + b
    b= y+1/3 x=3+5/3= 4 2/3 which is not 4/5
    Did I make an error?

  • Math -

    I Have no idea...I put in the #s so that it was 3=1/3(5)+b

  • Math -

    I see what I did wrong, forgot the negative sign.

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