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Write the slope intercept form of an equation for the line that passes through (5,3) and is parallel to x+3y=6 . Please help me solve!!!!!!!!!!

7 answers

well that is not right at all.

y=-1/3 x + b
b= y+1/3 x=3+5/3= 4 2/3 which is not 4/5
Did I make an error?

I see what I did wrong, forgot the negative sign.

How would you solve for b?

put y=3, x=5 into

y=-1/3 x+ b
solve for b.

ok thank you!! I got y=1/3x+4/5

I Have no idea...I put in the #s so that it was 3=1/3(5)+b

put the given equation into slope intercept form.

y=-1/3 x +6
so the slope is -1/3

Now, your new line will be of the form

y=mx+b. To be parallel, it must have a slope of -1/3.
y=-1/3 x + b
Now put the point on the line (5,3), and solve for b, and you have it, both m, and b.

Did you know?

To find the slope-intercept form of an equation for a line that is parallel to a given line, you need to know the slope of the given line. In this case, the line is represented by the equation x + 3y = 6. To determine the slope, rearrange the equation to y = mx + b form, so it becomes 3y = -x + 6 or y = (-1/3)x + 2. The slope of this line is -1/3. Now that we have the slope, we can use the point-slope form of a line, which is y - y1 = m(x - x1). Since the line we want to find is passing through the point (5,3), we can substitute these values in the equation to get y - 3 = -1/3(x - 5). Simplifying further, we get y - 3 = -1/3x + 5/3. Finally, rearrange the equation into slope-intercept form by isolating y on one side, obtaining y = -1/3x + 14/3. This is the equation for the line that passes through (5,3) and is parallel to x + 3y = 6.