Math
posted by Izzy .
Write the slope intercept form of an equation for the line that passes through (5,3) and is parallel to x+3y=6 . Please help me solve!!!!!!!!!!

put the given equation into slope intercept form.
y=1/3 x +6
so the slope is 1/3
Now, your new line will be of the form
y=mx+b. To be parallel, it must have a slope of 1/3.
y=1/3 x + b
Now put the point on the line (5,3), and solve for b, and you have it, both m, and b. 
How would you solve for b?

put y=3, x=5 into
y=1/3 x+ b
solve for b. 
ok thank you!! I got y=1/3x+4/5

well that is not right at all.
y=1/3 x + b
b= y+1/3 x=3+5/3= 4 2/3 which is not 4/5
Did I make an error? 
I Have no idea...I put in the #s so that it was 3=1/3(5)+b

I see what I did wrong, forgot the negative sign.
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