i already asked this question for how to divide
(x^2 +2x) / 2x-1
i need to find the quoyient not how to simplify it. I need to use the quotient in order to graph an oblique asymptote.
can it not be divided?
If you divide it you will get a messy remainder.
(x^2+2x)/(2x-1) = x*[x+2)/(2x-1)]
There will be an asymptote along the line x = 1/2.
thank you very much :)
To determine if the expression (x^2 + 2x) / (2x - 1) can be divided further, we need to perform long division or synthetic division. This will allow us to check if the numerator is divisible by the denominator.
Using long division:
____________________
2x - 1 | x^2 + 2x + 0
- ( x^2 - x )
______________
3x + 0
The remainder is 3x+0, which means the expression cannot be divided further. Thus, the quotient would be x + 3/2.
However, it seems you want to graph an oblique asymptote. For an oblique (or slant) asymptote to exist, the degree of the numerator should be exactly one greater than the degree of the denominator. In this case, both the numerator and denominator are of degree 1, so there is no oblique asymptote.
The correct approach for graphing the equation would be to identify the horizontal asymptote, which occurs when the degree of the numerator is less than or equal to the degree of the denominator. In this case, both the numerator and denominator have the same degree (1). Hence, the equation has a horizontal asymptote at y = a/b, where a and b are the leading coefficients of the numerator and denominator, respectively.