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A jar contains four red, four yellow, and three green jelly beans. If Joan and Jim take one jelly bean each, the probability that they both take a red jelly bean is?

  • Probability -

    prob for Joan, then Jim = (4/11)(3/10) = 12/110 = 6/55
    prob for Jim, then Joan = 6/55
    so prob = 6/55 + 6/55 = 12/55


    using combinations,
    prob they both pick red
    = C(4,1)xC(3,1)/C(11,2) = 12/55

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