9th grade
posted by jordan .
3 over the square root of 6

3/sqrt6= sqrt3*sqrt3/(sqrt2*sqrt3)
= sqrt3/sqrt2=sqrt3*sqrt2/sqrt2*sqrt2
= 1/2 sqrt6 
its supposed to be

I THINK IT I SUPPSOED TO BE 1.2
posted by jordan .
3 over the square root of 6
3/sqrt6= sqrt3*sqrt3/(sqrt2*sqrt3)
= sqrt3/sqrt2=sqrt3*sqrt2/sqrt2*sqrt2
= 1/2 sqrt6
its supposed to be
I THINK IT I SUPPSOED TO BE 1.2