calc
posted by Freddy .
What are the first and second derivatives of y = (1/x^2)(1/(x2)^2)?

I will do the first...
y'= 2/x^3  dy/dx (1/(x2)^2)=
= 2/x^3 +2/(x1)^3
check that. 
Yes, that is what I got as well. So would we have to go further, or does that suffice? Thank you.

But isn't it supposed to be 2/x^3  2/(x2)^3?
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