# Pre Calc

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My question is I^793

I think the answer is just I because it is the only number that can go into it. Is that correct?

• Pre Calc -

are you looking for factors of x^793?
or i^793, where i is the sqrt(-1)?

factors of x^793 are very numerous. x^793 is not a prime number.

i^793=i^792 * 1
Now consider
i^2=-1
i^4=1
i^6=-1
so the conclusion is that i^(4n-2) is -1
otherwise, i to even is 1
WEll, is 792=4n-2
4n=794, or n is not an integer, so
i^792=1
finally, i^792*i= i and it has only one factor, i.

• Pre Calc -

So I was correct the answer is i right?

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