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A 13.9 kg block is dragged over a rough, horizontal surface by a 70.7 N force acting at 19.8 degrees above the horizontal. The block is displaced 4.55 m, and the coefficient of kinetic friction is 0.298.

How much energy is lost due to friction?

  • physics -

    break the 70.7N force into vertical and horizontal components.
    The vertical component reduces weight, so figure the normal force (and friction) from that.

    frictionforce=(13.9g-70.7Sin19.8)mu
    work=frictionforce*distance

    Now notice that this does not equal the horizontal component of force*distance. So, the block has to accelerate.

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