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Afarmer must purchase 100 animals. He must spend exactly $100. He must have at least one of each animals. Sheep cost $.50, cattle cost $1.00 and horses cost $10

  • math -

    First of all let me predict that there is no unique answer.
    Here is why...
    Let the number of horses be x
    let the number of cattle by y
    let the number of sheep be 100-x-y

    then 10x + y + (1/2)(100-x-y) = 100
    multiply 2 to get rid of fractions.
    20x + 2y + 100 - x - y = 200
    y = 100 - 19x
    Of course we know that x and y must be natural numbers, (can't have 1/2 a cow)

    so the largest value that x can have is 5
    x=5, then y= 5 and 100-5-5 = 90
    so 5 horses, 5 cattle and 90 sheep

    let x = 4, y = 24, 100-4-24 = 72
    so 4 horses, 24 cattle and 72 sheep

    let x = 3, y = 43 100-3-43 = 54
    3 horses, 43 cattle and 54 sheep
    etc.

    each of the above combinations will cost $100

    (looks like this is from a book printed in the 1800's. Time for the schoolboard to upgrade)

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