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can someone actually show me all the steps to finding this deriviative. I keep doing the problem out and getting the wrong answer.

Find the deriviative of:


  • math -

    What is under the square root sign? the way you have written it, it is the argument of the sine function, 2t

    Assuming that is it

    y= INVsin(sqrt2t)
    I am going to shift to arcsin notation, so we don't get messed up in power notation.
    y=arcsin u where u=sqrt2t
    y'=1/(1-u^2) du/dx
    and du/dt= 1/(2sqrt2t) * 2 or 1/sqrt2t


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