Algebra
posted by Adriana .
How do you factor 1/2x^3x so that the zeroes can be found? Thank youAdriana

I think you mean
1/(2x^3x)
factoring the denominator
x(2x^21)= x(xsqrt21)(xsqrt2+1) 
(1/2)x(x^2  2) = 0
x = 0 or x = ± √2 
See how the same question can be interpreted in more than one way if you don't use brackets?
I read it as (1/2)x^3x
bobpursley read it as 1/(2x^3x)
or why not 1/(2x^3)  x ?
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