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math

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using method of partial fractions to decompose this 1/(x-3)(x+3)

is 1/6(x-3)-1/6(x+3) correct or have i gone wrong somewhere

  • math -

    I get

    1/(x-3)(x+3) = A/(x-3) + B/(x+3)

    1 = (x+3)A + (x-3)B

    1 = x(A+B) + 3A -3B

    -> A + B = 0 -> A = -B

    -> 3A - 3B = 1 -> A = 1/6; B = -1/6

    = (1/6)(x-3) - (1/6)/(x+3)

  • math -

    thanks so it is the same thank god for that

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