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how much tension must a rope withstand if it is used to accelerate a 1200-kg car vertically upward at .80 m/s^2?

Force required to accelerate the car vertically = m * (v^2)

= 1200 * (0.8^2)

= 1200 * 0.64

This force will be equal to the tension on the rope.

these are the answer choices though

Problem 10
13000 N
12000 N
11000 N
10000 N

13000N
12000N
11000N
10000N

tension=mg+ma=m(9.8+.8)= to two decimal places.

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