Physics
posted by Bill .
A baseball player hits a home run that just barely clears the 12m high fence in right field, 94m from home plate. If the ball was at a height of 1m when hit, and its initial path after it left the bat was at an angle of 35 degrees above the horizontal, what was the ball's initial speed when it left the bat?

break vi into horizontal and vertical components
94=v*cos35*t in the horizontal, find t, the time in air.
Vertical
12=1+vsin35*t4.9t^2 solve for v, knowing t. Use the quadratic equation. 
You will likely not need to use the quadratic equation.