Algebra
posted by Anonymous .
Solve x^2 3x is greater than or equal to 10
Would the solutions be x=5 and x= 2?

no, you forgot about the inequality condition.
You must have had
(x5)(x+2) ≤ 0
here is a neat way to finish it
draw a line and mark the "critical values" of 2 and +5
this splits the line into 3 segments
1. x < 2
2. x between 2 and 5
3. x > 5
pick any x you want in each of the segments to test . You don't actually have to find the value just the +/ situation
1. let x = 10 , so ()() > 0 , NO
2. let x = 0 , so ()(+) < 0 YEs
3. let x = 10, then (+)(+) > 0, NO
so every value of x between 2 and 5 inclusive will work..
2 ≤ x ≤ 5 , x any real number