Math
posted by Matt .
Two cards are drawn without replacement from an ordinary deck of 52 playing cards. What are
the odds against drawing a club and a diamond?

I would figure the odds of getting a club and diamond, then..
Pr(club and diamond)= 13/52*13/51
Now, Pr (not getting club and diamond)= 1Pr(club and diamond).
You can then figure the odds.