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Two cards are drawn without replacement from an ordinary deck of 52 playing cards. What are
the odds against drawing a club and a diamond?

  • Math -

    I would figure the odds of getting a club and diamond, then..

    Pr(club and diamond)= 13/52*13/51

    Now, Pr (not getting club and diamond)= 1-Pr(club and diamond).
    You can then figure the odds.

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