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Chemistry

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The kinetic energy of a rolling billiard ball is given by {\rm{KE}} = 1/2\,mv^2 . Suppose a 0.17-{\rm kg} billiard ball is rolling down a pool table with an initial speed of 4.5 m/s. As it travels, it loses some of its energy as heat. The ball slows down to 4.0 m/s and then collides straight-on with a second billiard ball of equal mass. The first billiard ball completely stops and the second one rolls away with a velocity of 4.0 m/s. Assume the first billiard ball is the system

How do I calculate work for a problem like this? I know how to calculate kinetic energy, but this question is asking for q and w.

Could someone please explain the steps it would take to answer a problem like this? Thank you.

  • Chemistry -

    According to the Work-Energy Theorem,
    Work = Ek(final) - Ek(initilal)

    Ek(initilal) = (1/2)mv^2 = (1/2)(0.17kg)(4.5 m/s)^2

    Ek(final) = (1/2)mv^2 = (1/2)(0.17kg)(4.0 m/s)^2

    Work = ?__________

    NOTE: This looks like a Physics question.

  • Chemistry -

    -1.4 J

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