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Calculus I

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Hi, I'm trying to figure this out, but the answer I keep coming up with is incorrect. Can anyone help me out? Thanks.

Problem: y=2(6-x^2)^5

I know I'm supposed to use the chain rule, but I'm getting confused.

  • Calculus I -

    y'= 5*2(6-x^2)^4 * (-2x)

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