solve:
14. ln(1/x) = -2
16. lnx + ln(x+2) = ln(x+6)
22. ln(lnx) = 1
I will do one
a) take the antilog of each side
1/x=e^-2
x= e^2
b) remember ln a + ln b= ln(a/b)
c) antilog ln x= e^x
ln e^0=1
I will be happy to critique your thinking.