BC Calculus
posted by Bob .
lim x >infinity (e^x/lnx)
I got infinity/0 but is that allowed to be my answer?
what about this one:
limx>infinity (sqrt of x /e^x)
i got 0/infinity for this.

on the first, L'Hopitals rule
lim= e^x/ (1/x)= xe^x inf
second: lim= 1/2 (1/sqrtx)*(1/e^x) looks like zero. 
For the first one, is it infinity?
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