# Math

posted by .

f(x+1)=8x^2+x-3

f(-x)=8x^2+x-3

work:
#1 8(x+1)(x+1)+x-3 then FOIL
8(x^2+x+x+2)+x-3
8x^2+16x+16+x-3
*8x^2+17x+13
#2 8(-x)^2-x-3
8x-x-3
*7x-3

I know on the first one you FOIL but im still getting it wrong?? The second one i thought was simple but im getting it wrong

• Math -

#1 8(x+1)(x+1)+x-3 then FOIL
8(x^2+x+x+2)+x-3 ****Nope, lots of errors, so here is what it should be..
8(x^2+x+x+1)+ (x+1)-3

2)8(-x)^2 + (-x) -3
8x^2-x-3

## Similar Questions

1. ### Algebra

Is there a shortcut to foiling an equation?
2. ### To Jasmine20 - FOILing

Try this website to learn about FOILing better: Go to Google and type in "FOIL" Click the first option (it starts with algebra.help........) If you can't find the exact website, just look through Google to find a lesson on FOILing. …
3. ### math

Volume of Aluminum Foil. One cubic centimeter of aluminum weighs 2.7 grams. If a piece of aluminum foil weighs 5.4 grams, find the volume of the aluminum foil.
4. ### physics- Electromagnetic waves

A square piece of foil with area A = 5.0 × 10^-4 m^2 and mass m = 5.0 × 10^-5 kg is suspended along one edge and hangs under its own weight. When light is incident perpendicular to the foil,the foil bends and reaches an equilibrium …
5. ### physics- Electromagnetic waves

A square piece of foil with area A = 5.0 × 10^-4 m^2 and mass m = 5.0 × 10^-5 kg is suspended along one edge and hangs under its own weight. When light is incident perpendicular to the foil,the foil bends and reaches an equilibrium …
6. ### physics

A square piece of foil with area A = 5.0 × 10^-4 m^2 and mass m = 5.0 × 10^-5 kg is suspended along one edge and hangs under its own weight. When light is incident perpendicular to the foil,the foil bends and reaches an equilibrium …
7. ### Math

9(x+2)(x+1)-2(x+2)-4(x+1)=0 I'm in the middle of solving an equation. I know that you have to FOIL but how did they get 9(x^2+3x+2)-(4x+4)=0 ?
8. ### Chemistry

The dimensions of aluminum foil in a box for sale at a supermarket are 66.6 yards by 12 inches. The mass of the foil is .83kg. What is the thickness of the foil (in cm)?
9. ### Math

My math teacher said to use the FOIL (First Outer Inner Last) property to simplify these quadratic equations I have made from looking at two parabolas. Here are my equations & how would you use the FOIL property on each of the equations …
10. ### Chemistry

I keep getting the wrong answer? I know there is one similar to this on here but I keep getting the wrong answer. The gold foil Rutherford used in his scattering experiment had a thickness of approximately 6×10^−3mm. If a single

More Similar Questions