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where is the vertex of the graph of y=x2+6x-2?

  • math -

    complete the square:
    y=x2+6x-2
    = x^2 + 6x + 9 - 9 -2
    = (x+3)^2 - 11

    so the vertex is (-3,-11)

    or

    for y = ax^2 + bx + c, the x value of the vertex is -b/(2a)
    sub that back in the original equation to get the y of the vertex.
    x of vertex = -6/2 = -3
    y = (-3)^2 + 6(-3) - 2 = -11

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