HELP! How do I graph this equation?
y+ __-x___ -3
4
Please clarify the equation - there is no "=" signs, and it is unclear what the blanks mean. If you want to graph it in terms of variables that affect shifts and stretches, arbitrarily define them.
If you are looking at this equation
y/4 + -x/-3 =0 then
multiply both sides by 12
3y+4x=0
y= -4/3 x which is easy to graph.
I am uncertain of what your "equation" is.
To graph this equation, you need to simplify it first.
The equation you provided is:
y + (1/4)(-x) - 3 = 0.
To graph this equation, you can start by isolating y on one side:
y = - (1/4)(-x) + 3.
Now, you have the equation in slope-intercept form (y = mx + b), where:
- m is the slope of the line, and
- b is the y-intercept.
In this case, the slope (m) is (1/4), and the y-intercept (b) is 3.
To graph the line, follow these steps:
1. Plot the y-intercept point on the graph, which is (0, 3). This represents the point where the line crosses the y-axis.
2. From the y-intercept point, use the slope (1/4) to find the next point on the line. The slope represents the change in y for every one unit change in x. So, for every 4 units you move to the right (positive x direction), you will move 1 unit up (positive y direction). From the y-intercept, move four units to the right and one unit up, and plot that point.
3. Repeat step 2 to find more points on the line. For example, from the second point you plotted, move four units to the right and one unit up, and plot that point. Repeat this process until you have sufficient points to sketch a straight line on the graph.
4. Connect the plotted points with a straight line.
Note that since the equation you provided is in slope-intercept form, it represents a straight line.