Differential Calculus

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Given that p=(2q^2-5)^2. when q=3, it is increased by 0.7%. find the appropriate percentage in p.

solution
dp = 2(2q^2-5) (2dq)
dp = (4x(18-5)(0.7%)
dp = 4(13)(0.7%)

am lost from here

is dp=52x0.7/100= 0.364%


Responses


Differential Calculus - bobpursley, Friday, August 14, 2009 at 1:52pm
p=(2q^2-5)^2

dp=2(2q^2-5)(4q)dq

ok from here

dp= -8

  • Differential Calculus -

    you have the expression for dp.

    q=3, dq=.007*3

    Now solve for dp and solve for P at q=3

    percentage change in p then is dp/p divided by 100.

  • Differential Calculus -

    y^4=c(x^2+4y^2)

  • Differential Calculus -

    y^4=c(x^2+4y^2)

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