What would happen if you reacted potassium dicarbonate with HCL and NaOH?
The question is a little confusing. I don't know what potassium dicarbonate is. Potassium carbonate is K2CO3.
oops sorry :S I meant Cromate. Potassium Dichromate. In a lab that I did I mixed 0.1 M K2CrO4 with 2 drops of NaOH and I added Ba(NO)2 until I noticed a color change. When I did this, the K2CrO4 which was initally yellow formed a white precipitate and on the top there was clear orange liquid. Why did that happen? How did the precipitate form?
The ppt is BaCrO4 (I think you mixed it with Ba(NO3)2.
The orange color comes from the equilibrium between CrO4 ion and Cr2O7^-2. Look up the equilibrium on google. I have problems at home.
Thanks :)
To determine what would happen when potassium dicarbonate (KHCO3) is reacted with hydrochloric acid (HCl) and sodium hydroxide (NaOH), we first need to examine the chemical reactions involved.
The reaction between KHCO3 and HCl can be represented as follows:
KHCO3 + HCl -> KCl + H2O + CO2
This reaction results in the formation of potassium chloride (KCl), water (H2O), and carbon dioxide (CO2).
Now, let's consider the reaction between NaOH and HCl:
NaOH + HCl -> NaCl + H2O
This reaction leads to the formation of sodium chloride (NaCl) and water (H2O).
If we combine both reactions, we have:
KHCO3 + HCl + NaOH -> KCl + H2O + CO2 + NaCl
In this case, the overall reaction results in the formation of potassium chloride (KCl), water (H2O), carbon dioxide (CO2), and sodium chloride (NaCl).
In summary, when KHCO3 is reacted with HCl and NaOH, the products obtained would be KCl, H2O, CO2, and NaCl.