Math
posted by B.B. .
Can someone explain this question to me? I don't understand it. Show how to find the quotient 18 divided by (6) by using A. The ideas of division as finding a missing factor. B. The procedures for integer division. Thanks.

what do you mean by A? if 18 divided by 6 the answer is 3.

A. Because 3*6 = 18, and you have the factor 6, the remaining factor must be 3.
B. I assume it wants you to show your work for long division.
Note: it would help if you were more clear in posing the question. 
As mentioned above, it is not clear what is to be demonstrated. I will present another attempt.
Factorize 18 into prime factors. Since division by negative numbers is possible, include two factors of 1. So
18 = (1).(1).2.3.3
Now organize the prime factors into two groups A (in bold) and B (italized).
18 = (1).2.3.(1).3
Therefore 18/(6) equals
group B=(1).3= 3
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