I am having a hard time figuring out the distane between two points the points are (9.8,-9.9)(-7.5,-5.5)I have the formula but i continue getting the wrong answer.
Between those two points, there's a change in x (the horizontal leg of a right triangle) and a change in y (the vertical leg of a right triangle). The distance between them is therefore the hypotenuse of the right triangle.
x^2+y^2 = distance^2
(it's the Pythagorean Theorem, because the distance IS the hypotenuse)
x is the CHANGE in x, and y is the CHANGE in y (which create the horizontal and vertical legs, respectively).
So:
(-7.5-9.8)^2 + (-5.5--9.9)^2 = (-17.3)^2 + (-5.5+9.9)^2 = (-17.3)^2 + (4.4)^2 = 299.29 + 19.36 = 318.65
ANSWER: The distance between the two points is 318.65 units.
that is the answer i have but it is not correct. i guess i am suppose to reduce it and square the answer. I have tried another problem. Find the distance between the pair of points (-6.2,4.6)(-4.5,0.6) i have the distance as 141.50 and their answer is 4.35. how did they get this answer i squared 141.50 and still did not get 4.35.
Whoops! Forgot to take the square root. Duh!
To calculate the distance between two points (x1, y1) and (x2, y2), you can use the distance formula:
d = √((x2 - x1)^2 + (y2 - y1)^2)
Let's apply this formula to your points (9.8, -9.9) and (-7.5, -5.5):
Step 1: Identify the coordinates
(x1, y1) = (9.8, -9.9)
(x2, y2) = (-7.5, -5.5)
Step 2: Substitute the values into the formula
d = √((-7.5 - 9.8)^2 + (-5.5 - (-9.9))^2)
Step 3: Calculate the differences
d = √((-17.3)^2 + (-5.5 + 9.9)^2)
d = √(299.29 + 20.24)
d = √319.53
Now, we can calculate the square root of 319.53 to find the distance:
d ≈ 17.88
Therefore, the approximate distance between the points (9.8, -9.9) and (-7.5, -5.5) is 17.88 units.