Given that y=x^2+2x-3
When x is -3 what is y?
Is the ans 0?
When x is 1 what is y?
Is the ans 0?
if x=-3, then y=-3, not zero:
y=-3^2-6-3
y=6-6-3
y=-3
Does this make sense?
if x=1, then y=0, you are correct:
y=1^2+2-3
y=1+2-3
y=3-3
y=0
Does this make sense?
Hope this helps!! :-)
Sally has made a mistake. (-3)^2 = 9 not 6.
y=-3^2-6-3 = 9 - 6 - 3 = 0
The second value solution is correct.
I hope this helps a little more. Thanks for asking.
To find the value of y when x is a specific number, you need to substitute that number into the equation and solve for y.
Let's start with the first question:
When x is -3, we substitute -3 into the equation y = x^2 + 2x - 3:
y = (-3)^2 + 2(-3) - 3
y = 9 - 6 - 3
y = 0
So, when x is -3, the value of y is indeed 0.
Moving on to the second question:
When x is 1, we substitute 1 into the equation y = x^2 + 2x - 3:
y = (1)^2 + 2(1) - 3
y = 1 + 2 - 3
y = 0
So, when x is 1, the value of y is also 0.