Write a slope-intercept equation for a line with the given characteristics:
m = 2/3 passes through (-4,-5)
I got an answer but would like to compare to see what someone else gets. Thanks!
y=mx+b
put in x,y, and m, then solve for b.
I came up with 7 2/3 is this correct, and if so do i need to turn it into an improper fraction? Thanks
subbing into bob's equation...
-5 = (2/3)(-4) + b
-15 = -8 + 3b
b = -7/3
so your equation is
y = (2/3)x - 7/3
How can this be? I got -8/3 because I multiplyed 2/3 and -4..Is this correct?
I usually clear my fractions, in this case I multiplied each term by 3
ok, your way...
-5 = (2/3)(-4) + b
-5 = -8/3 + b
-5 + 8/3 = b
-15/3 + 8/3 = b
-7/3 = b
see how much more complicated it gets if you keep the fractions ?
Thank you, I see how complicated it is when keeping the fractions. It makes sense now, thanks!
To write a slope-intercept equation for a line, we need to use the formula: y = mx + b, where m is the slope and b is the y-intercept.
Given that the slope (m) is 2/3, we can substitute this value into the equation: y = (2/3)x + b.
We also know that the line passes through the point (-4,-5). To find the y-intercept (b), we can substitute the x and y coordinates of the given point into the equation and solve for b.
Using the point (-4,-5), we have: -5 = (2/3)(-4) + b.
Now let's solve for b:
-5 = (-8/3) + b
Multiply each term by 3 to get rid of the fraction:
-15 = -8 + 3b
Add 8 to both sides:
-7 = 3b
Divide both sides by 3:
b = -7/3
So the value of b is -7/3.
Now we can write the slope-intercept equation for the line with the given characteristics:
y = (2/3)x - 7/3
Thus, the slope-intercept equation for the line is y = (2/3)x - 7/3.
You can compare your answer to this solution to check if you got the same equation.