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How do i write an equation in point slope form of a line that passes through (6,5) and has a x intercept of -3...also how do i make it into slope intercept form

  • math -

    the x-intercept of -3 corresponds to the point (-3,0)
    so the slope is (5-0)/(6+3) = 5/9

    then
    y - 5 = (5/9)(x-6)
    9y - 45 = 5x - 30

    9y = 5x + 15
    y = (5/9)x + 15/9
    y = (5/9)x + 5/3

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