posted by Anon .
When hydrochloric acid reacts with magnesium metal, hydrogen gas and aqueous magnesium chloride are produced. What volume of 1.0 M HCl is required to react completely with 4.00 g of magnesium
i did 4.00g x (mol/24.31 g Mg) x (2 mol HCl/1 mol Mg) x (L/!.0 mol HCl) = .329 L
why is this wrong?
It looks ok to me, too. Perhaps the answer should be in mL and not L. Check the problem and your typing. Make sure all of the numbers and units agree.
I don't see an error.
I just noticed that the molarity of the HCl is 1.0 M; therrefore, you have only two significant figures. Thus the answer should be reported as 0.329 = 0.33 L tp 2 s.f. That may be the problem.
thanks that worked