9th grade Algebra
posted by mike .
how do i solve this?!?!
4x2y=32
3x5y=11

I would multiply the top equation by 5, and the bottom equation by 2
20x10y=160
6x10y=22
then subtract the bottom equation (remember to change the signs)
26x=182 solve for x. 
alright i got x=7 but now what do i do?

Go back to either of the original equations, put in 7 for x, and solve for y.

so for example
4(7)2y=32 or 3(7)5y=11
and then it equals 282y=32 or
215y=11
then what from their this is driving me insane! 
add 21 to each side.
divide each side by 5
I think the answer is y=2,but you better check. 
Yep, 2 is almost right, but not quite. Check to see why.

i honestly cannot not get this problem, i guess it wont kill me to miss 1 assignment

2x+3y=12

2x+y=10