4x+3y=5
x-3y=5
solve by linear equations
It's a straight forward pair of simultaneous equations.
In this example just add the two equations to cancel out the y and find the x value.
Once you have the x value sub it back into one of the equations to find y.
Hope that helps
you use the elimination method for this one, well its the easiest way since your y's already cancel out. you would add your x's and your 5's together, then divide. that's when you get x=something then you sub your x answer in either one of the equation and you will get y. hope i was of some assistance!
Use the matrix method to solve the system of equations 2x + 4y = 8 and 6x + 3y = -3. The resulting matrix is:
To solve the system of linear equations, we can use the method of substitution or the method of elimination. Let's use the method of elimination:
Step 1: Multiply the second equation by 4 to make the coefficients of y in both equations cancel out when added together.
4(x - 3y) = 4(5)
4x - 12y = 20 (equation 3)
Step 2: Add equation 3 to equation 1 to eliminate the term with y.
(4x + 3y) + (4x - 12y) = 5 + 20
8x - 9y = 25 (equation 4)
Now, we have a new equation, equation 4, with only x and y.
Step 3: Solve equation 4 for x or y.
First, let's solve equation 2 for x:
x = 5 + 3y (equation 5)
Substitute equation 5 into equation 4:
8(5 + 3y) - 9y = 25
40 + 24y - 9y = 25
40 + 15y = 25
15y = 25 - 40
15y = -15
y = -15/15
y = -1
Step 4: Substitute the value of y back into equation 2 to solve for x.
x - 3(-1) = 5
x + 3 = 5
x = 5 - 3
x = 2
Therefore, the solution to the system of equations is x = 2 and y = -1.