Pre Calc

posted by Anonymous

Can someone help me understand how to do this:
I need to find two solutions to the problem
(x-2)^2 + (y+3)^2 = 9

  1. Anonymous

    i tried simplifying it down to
    x^2 - 4x + y^2 + 6y + 4 = 0
    but I don't know if I'm on the right track. Can anyone help?

  2. GanonTEK

    To me that doesn't seem like a complete question. You have 1 equation with 2 unknowns. You need a minimum of 2 equations to find 2 unknowns.

    Another way of looking at it is that the above equation is the equation for a circle with center (2,-3) and radius 3.
    So asking for two solutions for a circle doesn't make much sense.

    Are you sure that's the whole question?

    Hope that helps.

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